Find the derivative of the following function | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $f(x) = 5 \sec x + 4 \cos x$.Using the derivative rules for trigonometric functions:$\frac{d}{dx} (\sec x) = \sec x 	an x$$\frac{d}{dx} (\cos

Vedclass · Accepted Answer

$5 \sec x 	an x - 4 \sin x$

Vedclass · Answer

(A) Let $f(x) = 5 \sec x + 4 \cos x$.Using the derivative rules for trigonometric functions:$\frac{d}{dx} (\sec x) = \sec x 	an x$$\frac{d}{dx} (\cos x) = -\sin x$Applying the linearity property of derivatives:$f'(x) = \frac{d}{dx} (5 \sec x + 4 \cos x)$$f'(x) = 5 \frac{d}{dx} (\sec x) + 4 \frac{d}{dx} (\cos x)$$f'(x) = 5 (\sec x 	an x) + 4 (-\sin x)$$f'(x) = 5 \sec x 	an x - 4 \sin x$

Find the derivative of the following function: $5 \sec x + 4 \cos x$.

Similar Questions

The value of $\Delta \log f(x) + \Delta^{2}(3^{x})$ is

At $x=\frac{\pi^2}{4}$,find the value of $\frac{d}{d x}\left(\tan ^{-1}(\cos \sqrt{x})+\sec ^{-1}\left(e^x\right)\right)$.

The differential coefficient of ${x^6}$ with respect to ${x^3}$ is

Differentiate the function with respect to $x$: $\sin (ax+b)$

$\frac{d}{dt}(\tan t + t^2 \operatorname{cosech} t)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module